REQUIRED READINGS: Text, Ch. 20, and all that follows here. You may find it helpful to review Lessons 3 (the Sun) and Lesson 4 (observations of stars) before reading this section.
In Lesson 4 we described how astronomers classify stars according to intrinsic properties [mass M, surface temperature T, luminosity L, radius R] and plot these properties on diagrams relating pairs of these properties [L&T; M&L; M&R]. On such plots, more than 90% of the stars cluster in a thin band called the main sequence. If one of these properties -- say, M -- is specified, all other properties -- L, R, T, are also determined. Clearly, all these main sequence (M-S) stars have many things in common; the only reason they differ from each other is that they have different masses. Why is this true? It turns out that we can understand these relationships as the result of three basic physical principles.
In his famous 1920 article, The Internal Constitution of the Stars, Arthur S. Eddington described the three basic principles that form our modern understanding of the Sun and other main sequence stars. They are:
These three principles, expressed mathematically, are sufficient to explain all the observed properties of main sequence stars. We'll discuss them in turn.
Hydrostatic Equilibrium: This principle says that since M-S stars are neither expanding nor contracting, there must be a nearly exact balance between the outward pressure force of the hot gas within the star and the inward tug on the gas due to gravity. Since scientists knew (from laboratory experiments) how pressure depends on gas density and temperature, and how gravity depends on mass and radius, they could write an equation setting these forces equal. From this equation, they could infer the central temperature, Tc, of a star from its mass M and radius R. The result is
Tc = (1.6 x 107 K) M/R,
where
M and R are measured in units of the Sun's mass and radius, respectively. Note that Tc is much hotter than the surface temperature of the star. For example the Sun (with Tc = 1.6 x 107 K) has a surface temperature of about 6,000 K.With this equation and the observed mass-radius relation, we can deduce a very important clue to the structure of main sequence stars. The observations (see text, Figure 17.18a and
Lesson 4) show that main sequence stars have radius that is almost proportional to mass: R = M0.8. Plugging this observed fact into the above equation for central temperature gives the equation Tc = (1.6 x 107 K) M0.2, which implies that the central temperature of a main sequence star is extremely insensitive to the star's mass. For example, a blue giant star with mass M = 100 Solar masses will have Tc = 4 x 107 K, while a red dwarf with mass M = 0.1 Solar masses will have Tc = 1.0 x 107 K. While M ranges over a factor of 1000, Tc ranges over a factor < 4!There must be a reason why all main sequence stars have almost the same central temperature!
Energy Transport:
this principle describes how the tremendous heat energy in the interior of a star leaks out as the radiation we observe. Again, the appropriate equation follows from laboratory experiments. At the enormous temperatures inside stars, most of the radiation is X-rays. But even by 1920, people had been measuring how X-rays pass through matter -- specifically, how far X-rays could travel before they are absorbed or deflected by atoms. Eddington refers to these experiments in The Internal Constitution of the Stars.In class we had a little demonstration in which we threw dice to illustrate how radiation moves through matter by
diffusion, or random walk. The point is that if a photon is scattered by atoms in random directions many times, it will take much longer to escape from the center of the star than it would if it could travel out directly. For example, a photon would require only two seconds to travel from the center of the Sun to the surface if it could travel freely. But actually, it takes several thousand years for a photon to leak out of the Sun by diffusion.The experiments showing how X-rays pass through matter and a theory for diffusion are sufficient to determine the luminosity of a main sequence star from its mass, radius, and central temperature, i.e., to determine the mathematical function
L(M,R,Tc). Moreover, since the principle of hydrostatic equilibrium gives Tc(M,R), and we can determine Tc from the observed mass-radius relation, the mass alone is sufficient to determine the luminosity, i.e., these relations give the mass-luminosity relation L(M). In fact, this theory gives the formula L = M3.5, which is just the relationship between luminosity and mass that main sequence stars are seen to obey (see Lesson 4).Massive main sequence stars are much more luminous than the Sun for two reasons: (1) the gas inside massive stars has lower density, so the radiation can leak out more easily; and (2) the massive stars have much greater volume, so they contain much more radiation which can leak out.
The fact that the theoretical mass-luminosity relationship agrees with the observed one gives us more confidence that we truly do understand how the heat leaks out of main sequence stars.
Energy generation: we have already discussed the idea that the Sun derives its energy from nuclear fusion reactions in its core. Eddington understood that the energy that would be released by the fusion of four hydrogen atoms to form helium was hundreds of times greater than the Sun's internal heat energy. He realized that such fusion reactions must be going on inside the Sun; otherwise it would collapse in about 20 million years, as Kelvin and Helmholtz said.
But Eddington did not know how such reactions could take place. Indeed, he recognized there was an unsolved mystery. To quote from The Internal Constitution of the Stars: "But is it possible to admit that such a transmutation is occurring? It is difficult to assert, but perhaps more difficult to deny, that this is going on."
It would be another 30 years until this problem was solved. The solution was found in the 1950's by Professor Hans Bethe of Cornell University. Like many physicists of that time, Bethe had worked on the development of the atomic bomb and the hydrogen bomb, and so he knew a lot more about nuclear reactions than Eddington knew in the 1920s. In fact, the key insight about how nuclear fusion reactions could occur was provided by George Gamow, who was a Professor here at the University of Colorado. You will hear a lot more about Gamow later in this course. Bethe understood Gamow's theory of nuclear reactions and he also knew a lot of detailed experimental information about fusion reactions.
The reason that fusion reactions require such high temperatures to occur is that atomic nuclei repel each other very strongly by electrical forces. The nuclei cannot react with each other unless they come very close. This is unlikely enough for two nuclei; it would be virtually impossible for four hydrogen atoms to get close enough to stick together all at the same time. Therefore, Bethe understood that the fusion of hydrogen into helium must take place by a sequence of reactions in which other elements are formed as intermediate steps. He discovered two such sequences of reactions, both of which play a role in converting hydrogen into helium in main sequence stars. The first, which dominates in stars with masses comparable to the Sun and less, is called the proton-proton chain, which is illustrated below.

Click
here for a movie showing these reactions in sequence.The second, which dominates in more massive main sequence stars, is called the
CNO cycle. This reaction sequence is described on p. 422 of your text and here. Click here for another movie showing the CNO cycle.Bethe's work on nuclear reactions put the final piece in the puzzle of main sequence stars: why do they all have nearly the same central temperature? Remember, this result followed from the principle of hydrostatic equilibrium and the observed relationship between stellar mass and radius. Bethe showed why this should be so. He knew that the thermonuclear reactions that led to fusion of hydrogen into helium would be extremely sensitive to temperature. At temperatures less than 107 K, they won't go at all. One can regard this temperature as a kind of "kindling temperature," or minimum temperature required to initiate and sustain a reaction. Above the kindling temperature, say, at temperatures exceeding that in the center of the Sun, 1.6 x 107 K, the reactions will go extremely rapidly.
Stability of Main Sequence Stars:
This temperature sensitivity of thermonuclear reactions creates an elegant kind of thermostat that regulates the central temperature of main sequence stars, Tc, at a constant equilibrium value. If Tc rises above this value, the nuclear reactions pump heat energy into the stellar interior at a greater rate than the energy can escape by radiative diffusion. This extra heat energy causes the interior of the star to expand a bit, and this expansion actually causes the interior temperature to decrease a bit. But that reduces the rate of the thermonuclear reactions, which causes the temperature to drop back to the equilibrium value for which the thermonuclear energy production exactly balances the heat loss by radiative diffusion.As we shall see in the next lesson, not all stars are so stable. In dying stars, the thermostat can fail. Then, the star's core will explode, releasing all its nuclear energy in minutes rather than billions of years. A very big bomb, called a supernova.
A main sequence star is a wonderfully balanced mechanism, and we can all be thankful for that.
2. LIFETIMES OF MAIN SEQUENCE STARS
Armed with an understanding of how main sequence stars burn by fusing hydrogen into helium, astrophysicists were ready to return to the old problem that Eddington addressed so eloquently in
The Internal Constitution of the Stars. How long can stars run?This problem is analogous to determining how long a vehicle can run on a tank of gas. The answer is simple: divide the fuel available by the rate of energy consumption. For example, if your Subaru gets 30 miles to the gallon, it can go 300 miles on a 10 gallon tank. That means you can drive 10 hours at 30 miles per hour. But now suppose that you are driving a "sports utility vehicle," capable of crushing a Subaru without noticing. It has a bigger tank, say, 20 gallons. But it only gets 10 miles per gallon, so it can only go 200 miles, or less than 7 hours at 30 miles per hour.
From Einstein's formula E = mc2 and Aston's measurement of the masses of hydrogen and helium, Eddington knew how much energy would be released by the fusion of hydrogen into helium, and he understood that the Sun could continue to produce its present luminosity for about 1010 (10 billion) years before all the hydrogen in its burning core (about 10% of the total mass of the star) would be converted into helium.
But how long will the more massive main sequence stars live? For example, consider a luminous blue giant star in the Pleiades cluster (the cosmic Subaru), which has a mass about 6.3 times that of the Sun. and a luminosity about 630 times that of the Sun. Well, the fuel supply is up by a factor 6.3, but the energy consumption rate (the observed luminosity) is up by a much bigger factor (6.3)3.5 = 630. So the lifetime of this star will be less than that of the Sun (1010 years) by a factor of about 6.3/630 = 0.01. That brings its lifetime down to 0.01 x 1010 = 108 years. Evidently, the cosmic Subaru is more like a sports utility vehicle than a fuel-efficient compact!
Using the mass-luminosity relationship,
L(M) = M3.5 (see Lesson 4), it's easy to generalize this argument into an equation that gives the main-sequence lifetime, tMS, of any star in terms of its mass:tMS = tSun M/L(M) = 1010 years M/M3.5 = 1010 years M-2.5 ,
where masses and luminosities are measured in Solar units. Check it! Put in M = 10 Solar masses and see whether the answer agrees with our estimate for the blue giant star in the Pleiades. How long will a red dwarf star with M = 0.1 live?
We know now that the Sun has a main sequence lifetime of 10 billion years and that it has already lived for about 4.5 billion years. So it has already converted about half the hydrogen in its core into helium (see text, Fig. 20.2 and here;). In another 5.5 billion years, the core of the Sun will be pure helium. What happens then?
3. RED GIANTS AND HORIZONTAL BRANCH STARS
When all the hydrogen is gone from the core of the Sun, the heat that leaks out as radiation cannot be replenished by hydrogen fusion reactions. Then, the core must shrink as it loses energy, and it will do so in about 20 million years, just as Kelvin and Helmholtz had predicted.
When the core shrinks, the compression due to gravity will actually cause the gas to become hotter, not cooler. Moreover, the shrinking core is surrounded by hydrogen gas that was too cool to burn when the star was a main-sequence star. But now, as the core shrinks and becomes hotter, the temperature of the hydrogen surrounding this core will rise above the kindling temperature for hydrogen fusion reactions, and the hydrogen will begin to burn in a thin shell surrounding the helium core, which is not burning, as illustrated in Figure 20.3 of your text or
here. This shell burns fiercely, producing more luminosity than the core of the star did while it still had hydrogen to burn. In fact, the luminosity produced by the shell is so great that it cannot leak out of the envelope as fast as it is produced. Instead, it causes the outer envelope of the star to expand.We call the resulting star a
red giant. The radius of its photosphere swells up by a factor of 100 or more compared to the radius it had as a main sequence star, and its luminosity increases by a factor of a few hundred. Its interior structure is totally different from that of a main-sequence star (e.g., the Sun, Fig. 16.4). The distended outer part of the star has very low density. But the inner core of the star, which contains about half the mass, is very small (about the size of Jupiter) and very dense.When the Sun becomes a red giant, it will envelop the Earth, vaporizing the oceans and melting the rock into ceramic. People, if they exist then, should be prepared to colonize the Moons of Jupiter, or maybe Neptune or Uranus. Don't worry: we have plenty of time to get our rockets ready. But what will happen after that?
Helium burning:
the Sun will be a red giant for about 100 million years or so, as its helium core slowly continues to contract and get hotter. But then something remarkable happens. At temperatures above about 108 K (100 million), helium can fuse into carbon in a process called the triple-alpha reaction. It is described in your text, p. 424. See also this diagram and this movie. Since one carbon nucleus has less mass than the sum of three helium nuclei, this reaction releases energy (in the form of gamma ray photons). At sufficiently high temperatures some of the carbon will also fuse with another helium nucleus to form oxygen. But the energy yield per unit mass in these reactions is less (by a factor of about 1/7) than that from the fusion of hydrogen into helium.When the temperature of the helium in the core of the red giant star rises above 108 K, the triple-alpha reaction turns on suddenly, in a phenomenon called the
helium flash. The core suddenly expands due to the increased energy production. This expansion causes the hydrogen burning shell to diminish in luminosity, and this causes the outer envelope of the star to shrink back again, from a few hundred solar radii to about 10 solar radii. The resulting star is called a horizontal branch star, and its interior structure is illustrated schematically here.Horizontal branch stars are called so because of their locations on the Hertzsprung-Russell diagram, as illustrated in the figure below, which is a H-R diagram for a dense cluster of stars called M3 (which we shall discuss in more detail below. [Click
here to see an image of M3.]
Note that M3 has no luminous blue main sequence stars. In fact, the only main sequence stars (labeled MS) are solar type or redder. M3 has many red giant stars, labeled RGB, and horizontal branch stars, labeled HB, that lie on a horizontal strip. The HB stars have roughly the same temperature as the Sun and so have spectral types in the range A - G, but they are almost 100 times as luminous as the Sun. They are all burning helium in their cores.
But, after about another 50 million years or so, the helium in the core of the HB star all turns to carbon and oxygen, and these elements can't burn at the temperatures (100 - 200 million degrees) in the core of the HB star. Therefore, the carbon-oxygen core begins to shrink again. As it becomes hotter and denser, the surrounding helium begins to burn furiously in a shell. Once again, the shell burning produces more luminosity than can escape through the envelope of the star, so the star swells up again to a red giant star. But this star has a different internal structure than it did the last time it was a red giant (before it became a horizontal branch star). It contains a very dense carbon/oxygen core that is not burning, surrounded by a burning shell of helium, surrounded by a burning shell of hydrogen, surrounded by a hydrogen envelope. The internal structure is illustrated in Fig. 20.7 and
here.These kinds of red giant stars, called asymptotic giant branch stars, or
AGB stars, are indicated on the H-R diagram above (see also text, Figure 20.13). From the outside, they are indistinguishable from red giant stars. So we can't be sure, for example, whether Betelgeuse has a core composed of helium or of carbon/oxygen.To review the evolution of stars through the red giant and AGB stages, you should play with this wonderful
stellar evolution simulator, by Terry Herter of Cornell University.
4. INSTABILITY, MASS LOSS, AND PLANETARY NEBULAE
The most luminous stars are not very stable. Their luminosities are so great that the outward force exerted by the escaping radiation is almost equal to the gravitational force that holds the star together. As a result, blue giant stars lose mass from their outer envelopes in powerful stellar winds having huge (500 - 3000 km/s) velocities. According to theory, a main sequence star with mass greater than about 200 solar masses can't exist. If a star with greater mass begins to form, it will blow itself apart as soon as it begins to burn hydrogen in its core.
The most luminous main sequence stars known have luminosities equal to about 10 million Suns. These blue supergiants are very rare. There is a cluster of them in a nebula called 30 Doradus in a nearby galaxy, the Large Magellanic Cloud, that you can see
here and read about here. Just a few months ago, astronomers from UCLA, using a new infrared camera on the Hubble Space Telescope, discovered the current record holder, which you can read about here.Red giant stars tend to be more unstable than blue giant stars, because they are so distended that gravity has a relatively feeble hold on their outer atmospheres. Moreover, the enormous luminosity of red giant stars pushes the envelope outward as it diffuses outwards. As a result, every red giant star is losing mass in stellar winds. The outer part of the star is literally blowing out into interstellar space, at velocities ranging from 10 to 30 km/s -- huge by Earth standards but not so fast by interstellar standards. The mass loss rate in these stellar winds is so great that the star can lose half or more of its total mass during its red giant phase.
Some of the most luminous red giant stars are seen to pulsate, becoming brighter and dimmer over periods of a year or so. These are called "long period variables." AGB stars (described above) are even more unstable than red giants. Toward the end of their lifetimes, they are likely to expel almost all their hydrogen and helium envelope, leaving the carbon/oxygen core exposed. The expelled gas escapes into interstellar space and is seen as a glowing shell, called a
planetary nebula. The nebula glows in emission lines because it is heated and ionized by ultraviolet radiation from the carbon/oxygen core. (The name planetary nebula is a misnomer. Planetary nebulae have nothing to do with planetary systems. But the astronomers who first observed them thought they might be the sites of planet formation, and the name stuck.)Planetary nebulae are among the most beautiful objects in the sky. Some are fairly smooth and symmetrical, such as the famous
Ring Nebula in Lyra (a.k.a. M57), which you can see easily through the telescopes at the Sommers Bausch Observatory. Another one is the Helix Nebula (a.k.a. NGC7293). A Close-up of the Helix Nebula taken with the Hubble Space Telescope shows that the gas in this nebula is still being blown away by the tremendous radiation and stellar wind from its central star. Other planetary nebulae have strange and wonderful shapes, indicating that the mass ejection process is very complicated. You can find several images of planetary nebulae from the Hubble Space Telescope here. Be sure to read the captions.Many horizontal branch stars pulsate regularly. The luminous ones, resulting from the evolution of stars considerably more massive than the Sun, are called Cepheid variables. They pulsate regularly with periods ranging from 1 to 100 days. The less luminous ones are called RR Lyrae stars. Your text, pp. 490 - 491 describes how these stars regularly become brighter and dimmer as their radius swells up and shrinks back down. As we shall see later, these variable stars are very important for determining cosmic distances because astronomers can infer their luminosities by observing their pulsation periods.
After the AGB star has ejected its envelope as a planetary nebula, what is left is a very compact core of carbon/oxygen (perhaps covered with a thin layer of residual helium). What happens to this core?
As we have discussed, when the core of a star burns up all its fuel, it must begin to contract as it radiates away its heat energy. It contracts because the lost heat implies a loss of pressure support. Up to now, the only pressure that we have been considering is heat pressure. But at very high gas density, such as that encountered in the carbon/oxygen core of an AGB star, a new kind of pressure, called
degeneracy pressure, becomes comparable to or greater than the heat pressure. As we shall discuss below, this degeneracy pressure stops the contraction of the carbon/oxygen core.Degeneracy pressure is familiar to all of you. It is the pressure that prevents liquids and solids from being compressed. Squeeze on any solid object: it pushes back. Gas pressure is "squishy", as you can test by pumping your bicycle tire with a hand pump. But at a density of a few grams per cubic centimeter, ordinary matter becomes liquid or solid and is nearly incompressible. No apparatus on Earth can compress water (or steel) to half its volume. Moreover, the tendency of liquids and solids to resist compression is almost independent of their temperature. Liquids and solids do not shrink much when cooled, even to almost absolute zero temperature (-273 K). The same degeneracy pressure prevents atoms from collapsing.
Scientists gained a better understanding of this degeneracy pressure during the 1930s when they developed theory of
quantum mechanics, which explains the structure of atoms, molecules, and liquid and solid matter. With this theory, we can understand how matter at high density resists compression.The theory tells us that it is possible to compress matter, even at very high density, but that the necessary pressures are enormous. For example, even at the center of Earth the iron is only compressed by about 10% in volume. But at the center of Jupiter the pressure is sufficient to compress the matter by almost a factor of 2.
The density in the carbon/oxygen core of an AGB star (or the central star of a planetary nebula) is so great that this degeneracy pressure becomes greater than the heat pressure. But since degeneracy pressure doesn't require heat energy, it doesn't diminish when the carbon/oxygen core radiates away its heat. That means the star doesn't shrink anymore -- it simply cools off.
If the carbon/oxygen core that remains after a star has shed its outer envelope has mass less than 1.4 solar masses, it has come to the end of its life story. It has no nuclear reactions and it will have no further major structural changes. It will take many millions of years, however, before it cools off enough that it becomes invisible. We call such a star a
white dwarf star.As the white dwarf star cools, the carbon atoms will crystallize into diamond. Think of it: a single diamond with a mass equal to 300,000 times the entire Earth! But don't count on getting rich mining these diamonds. The gravity on the surface of a white dwarf star is something like 300,000 times the gravity on Earth, and you would weigh 30 million pounds there. Better just enjoy the thought that billions of such diamonds really exist.
In fact, astronomers have observed many white dwarf stars. Indeed, the brightest star in the sky, Sirius, is actually a binary star system consisting of Sirius A, a fairly luminous main sequence star (mass about 6 Suns), and Sirius B, a white dwarf. Click
here for an image of Sirius A and B. The radius of Sirius B, as inferred from Stefan's Law (see Lesson 4), is actually less than the radius of Earth. We know now that there are billions of white dwarf stars in the Milky Way galaxy, but we haven't observed very many because they are so faint and hard to find.The theory the structure of white dwarf stars was first worked out in 1930 by
S. Chandrasekhar while he was a graduate student at Cambridge University. Chandrasekhar's theory showed that a white dwarf star with mass equal to that of the Sun would have a radius less than that of the Earth. That implies that the average density of such a star would be greater than a million times the average density of the Earth -- a one ounce shot glass of white dwarf matter would weigh more than 100 tons!Chandrasekhar's theory also showed that the greater the mass of such a star, the smaller its radius would be. In fact, he found that if the star's mass exceeded 1.4 times the Sun's mass, the degeneracy pressure would not be strong enough to resist gravity and the star would collapse. We call this value of mass -- 1.4 Suns -- the
Chandrasekhar limit*. As you will see, this limit plays a fundamental role in determining the final fates of stars.
*
Arthur S. Eddington, also at Cambridge University, didn't believe this result, and in fact ridiculed the idea. But he was wrong.Actually, planets, such as Earth and Jupiter, are also supported by degeneracy pressure, so their structure is related to that of white dwarf stars, as illustrated by the blue curve in the mass-radius diagram below.
The axes of this diagram are labeled in logarithmic scale so that, for example, Jupiter, with mass = 10-3 solar masses and radius 60,000 km, has Log(Mass/Solar Mass) = -3 and Log(Radius/kilometers) = 4.8.
The blue curve shows the relationship between mass and radius for objects held up by degeneracy pressure (planets and white dwarf stars). One sees that the matter in planets lighter than Jupiter is almost incompressible, so that the radius increases with increasing mass. But in planets with masses greater than Jupiter's, the central pressure is so great that the matter there is crushed significantly. In fact, Jupiter is almost as big as a planet can be. If you could somehow shovel matter onto its surface, Jupiter wouldn't get much bigger. In fact, a planet with mass ten times that of Jupiter (we should call it a Brown dwarf star) would actually be smaller than Jupiter, and Sirius B (a white dwarf), which has mass about equal to the Sun, is smaller than the Earth!
Note also that the blue curve turns down vertically at Log(M/Solar Mass) slightly greater than 0 (i.e., at M = 1.4 Solar Masses), the Chandrasekhar Limit. That means that a white dwarf with mass greater than this value will collapse.
The green line on this mass-radius diagram represents the mass-radius relationship for main sequence stars. As we described, these stars are supported by heat pressure, not degeneracy pressure, and the relationship represented by the green line is a consequence of the fact that main sequence stars all have nearly the same central temperature. This line terminates at a mass of about 200 Suns, above which no stable main sequence star can exist (we think!).
We'll return to this diagram later to discuss the lines labeled "neutron stars" and "black hole limit".
As we discussed in Lesson 5, stars are not born in isolation; they are born in clusters containing many thousands of stars. Moreover, the timescale for a cluster of stars to be born from a dense interstellar gas cloud is a few million years -- far less than the typical lifetimes of most stars, which range from ten million years for the most massive stars to billions of years for stars like the Sun.
Before reading this section, it might be a good idea to review the observations of star clusters, which are discussed in your text, Section 17.10 and in Lesson 4. Now we are ready to address the last question in the summary of Lesson 4: Why are the types of stars found in globular clusters so different from those in open clusters? We now know the answer: globular clusters are very old, while open clusters are relatively young. As you will see, our understanding of this fact gives us a powerful tool to determine the ages of astronomical systems, even the universe itself.
The study of star clusters is an example of population dynamics, a technique that has wide-ranging application in all sorts of natural and social sciences. As the name suggests, the same technique can be applied to the study of human populations. For example, suppose we take a census of a large city and count people by height. We might find that about 80% -- 4/5 -- of all the inhabitants were between 4'8" and 6' 2" tall, and that about 20% of people were shorter. If we had data on ages as well, we would see that most of the people shorter than 4'8" were less than 16 years old. We might infer that 20% of the people were short because the average lifetime of people is about 80 years, so that people spend only 1/5 of their lifetimes under 16 years old, i.e., under 4'8". The logic is sound if the population of the city is stationary, so that roughly the same numbers of people are born and die each year.
But one could find towns where there are no little people (i.e., no children). Such dying towns, where all the people of child-bearing age have left and only old people remain, can be found in North Dakota, for example. Likewise, one can find new suburbs where nearly half the people are children.
All this makes sense because we understand the life cycles of human beings -- particularly the relationship between height and age. Since we know more about human development, we can make some pretty good guesses about the populations mentioned above -- for example: what fraction of the people in the city, town or suburb have gray hair; what fraction have young children; what fractions are male and female, etc. If we have census data on these fractions, we can check whether our guesses are right and improve our understanding of the history of the population and of human development.
Since we now know something about the life cycles of stars, we can regard clusters of stars as analogues of towns and apply the same kind of reasoning to analyze their populations. But there are some differences. The most important one is that stars, unlike human beings, do not all have similar life spans. The most massive stars remain on the main sequence (i.e., burn hydrogen in their cores) for only about 107 (10 million) years, while stars like the Sun remain on the main sequence for about 1010 (10 billion) years. That means that in a newborn star cluster, of age less than 107 years, even the most massive blue giant stars will still be on the main sequence, as illustrated here. But after 107 years, the most massive blue giants will have consumed all the hydrogen in their cores and will have become red giants (while the less massive stars will still be on the main sequence), as illustrated by the schematic color-magnitude diagram here. Compare this diagram with that of the Pleiades, shown below.

.
As time goes on, less massive stars also become red giants, and some of the stars that were previously red giants have evolved into white dwarf stars. This sequence of events is described
hereBut the diagrams are incomplete because they don't show the horizontal branch stars that are also found in these clusters. For example, compare the schematic color-magnitude diagram of a 10 billion year old globular cluster here with the real color-magnitude diagram of the globular cluster M3, which shows many horizontal branch stars as well as red giant stars. The observations used to construct this diagram were not sensitive enough to see the many white dwarf stars that must exist in M3, but the Hubble Space Telescope found many white dwarfs in the globular cluster M4. Below is a color-magnitude diagram of M4, showing the faint main sequence and white dwarf stars detected there (this diagram does not show the brighter red giants and horizontal branch stars in M4).
We define the
main sequence turnoff of a star cluster as the position on the H-R diagram of the most luminous star that remains on the main sequence. For example, the main sequence turnoff is located right next to the label "blue dwarf stars" in the diagram above.) As the diagrams above show, this point moves to lower luminosity and temperature as the star cluster ages. Since we have a theory that tells us how long stars of a given mass (or luminosity) can remain on the main sequence, we can infer the age of a star cluster from the location of the main sequence turnoff of its H-R diagram.The globular clusters are the oldest star clusters known. By comparing the main sequence turnoff points of their H-R diagrams with the theory of stellar evolution, astronomers find that the oldest globular clusters are 11.5 billion years old with an uncertainty of +/- 1.3 billion years (data are shown
here). This tells us something important about the universe itself. Of course, it must be at least as old as any star cluster that it contains -- i.e., at least 10.2 billion years old.
More than half of the stars in the sky belong to binary systems, and most of these are close binaries, in which the two stars are separated by only a few stellar radii and have orbital periods of days. We have seen how single stars evolve. Now we need to discuss the evolution of binary stars. As you will see, the possibility -- indeed, the certainty -- that these stars will interact with each other when they approach the end of their lifetimes opens a rich variety of new possibilities for the final fates of these stars and for the phenomena that we can observe.
The subject of interacting binaries is covered pretty well in your text, Section 20.6. So here I'll list a few important concepts you should know and a few links that you should check.
Mass Transfer in Binary Systems:
In all orbiting systems, there is a location called the Inner Lagrange Point (also called the L1 point), which is the place where the gravitational pull of the two objects is exactly equal, as illustrated in Figure 20.21 and 20.22 of your text. For the Earth-Sun system, for example, the L1 point is located at a point about 20 Earth diameters away from Earth toward the Sun. The SOHO satellites are located there. As Figure 20.21 shows, the L1 point is on a mathematical surface called the Roche Lobe. As a star swells up due to its evolution, its outer atmosphere will finally reach this Roche Lobe, as illustrated there. Then, gas will start to spill across the L1 point onto the other star.When both stars in a binary system are smaller than their respective Roche lobes, no mass transfer will occur. Such systems are called
detached binary systems. But when one star fills its Roche Lobe and begins to pour matter onto the other star, the system is called a semi-detached binary system. Finally, it is possible that the second star will also swell up so that it also fills its Roche Lobe. In that case, the stars merge into a common-envelope binary system, which has a single dumbell-shaped outer surface and two cores. In such systems, the cores may eventually merge to form a single star. But in some cases the system may expel its common envelope and turn back into a detached or semi-detached binary. Figure 20.21 of your text illustrates these various possibilities.
The "Algol Paradox":
We have already discussed Algol -- a binary star system that was known as the "Demon Star" because it was seen by the ancients to become dim periodically as the red star eclipsed the brighter blue star. The red star is bigger than the blue star. Evidently, it is nearing the end of its lifetime and becoming a red giant. But the red star is less massive than its blue companion, which appears to be a main sequence star. Here's the "paradox": we believe that both stars in a binary system are formed at the same time. We also believe that more massive stars evolve faster than less massive stars. So, how can it be that the less massive red star is more evolved than the more massive blue star in Algol?The answer (see text, Fig. 20.22) is that the red star was more massive, and that is why it is more evolved than the blue star. But when it ran out of hydrogen in its core and began to swell up, it passed its outer envelope over to the blue star. The blue star became more massive and the red star became less massive.
This process is illustrated very nicely in John Blondin's
Algol page. Be sure to hit the answer. That shows a realistic supercomputer simulation of how the gas passes from the evolved star to the less evolved star. In particular, the simulation shows how an accretion disk is formed due to the rotational motion of the gas as it is transferred in a binary system.The mass transfer that occurs in binary systems of various types leads to a variety of strange phenomena, as we shall describe in Lesson 7.
We began with the three basic physical principles needed to describe the structure of main sequence stars. The first principle,
hydrostatic equilibrium, told us how to infer the central temperatures of stars from their observed mass-radius diagram. The result showed us that all main sequence stars had very similar central temperatures, ranging from 107 K for the least luminous red dwarf stars to 4 x 107 K for the most luminous blue giants. The second principle, energy transport, describes how the radiation leaks out from the center of the star. This principle explains the observed mass-luminosity relationship of main sequence stars. The third principle, energy generation, describes how the energy that leaks out as radiation from the star is replenished by thermonuclear reactions in the core of the star. With the theory of nuclear reactions, it explains why the central temperatures of all main sequence stars should lie in such a narrow range as inferred from the first principle.Armed with an understanding of how stars work, we then proceeded to describe what happens to a star after it exhausts the hydrogen fuel in its core. We described how the interior structure and external appearance of the star changes as it evolves from a
main sequence (M-S) star, to a red giant (RG), to a horizontal branch (H-B) star, to an asymptotic giant branch (AGB) star, and finally to a white dwarf (WD), surrounded in its initial stages by a planetary nebula. You should review the diagrams of the interior structure of each of these kinds of stars.White dwarf stars are dying embers of stars, in which no nuclear reactions are taking place. They do not collapse because they are supported by
degeneracy pressure, a kind of atomic pressure that does not depend on heat. Degeneracy pressure can prevent the cores of stars from collapsing, but only if they have mass less than the Chandrasekhar limit of 1.4 solar masses.We can see all these kinds of stars in star clusters. In young clusters, most of the stars are main sequence stars. After ten million years or so, the most massive stars in the cluster have changed from blue giants to red giants. In clusters more than 10 billion years old, the only stars remaining on the main sequence have mass and luminosity less than the Sun, but the cluster contains many red giants, horizontal branch stars, and white dwarfs. By measuring the position of the
main sequence turnoff, astronomers can infer the ages of star clusters. They find that some globular clusters must be older than 10 billion years.Roughly half the stars in the sky belong to close binary systems. In such systems, the more massive star can transfer mass to the less massive one as it evolves to become a red giant. This mass transfer process solves the
Algol Paradox, a puzzle about the eclipsing binary system Algol. It also gives rise to a variety of spectacular phenomena that we will discuss in the next lesson.Last modified May 1, 1998
Copyright by Richard McCray